Download [PDF] October 2016 CAIE P2 Mark Schemes 1112 Mathematics Cambridge Lower Secondary Checkpoint

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[PDF] October 2016 CAIE P2 Mark Schemes 1112 Mathematics Cambridge Lower Secondary Checkpoint.pdf | Plain Text

This document consists of 11 printed pages and 1 blank page. IB16 10_1112_02/2RP © UCLES 2016 [Turn over Cambridge International Examinations Cambridge Secondary 1 Checkpoint M ATHEM ATICS 1112/02 Paper 2 October 2016 MARK SCHEME Maximum Mark : 50 IMPORTANT NOTICE Mark Schemes have been issued on the basis of one copy per Assistant examiner and two copies per Team Leader.

2 © UCLES 2016 1112/02/O/N/16 Question number 1 Part Mark Answ er Further Information (a) 1 3 (b) 1 35 Total 2 Question number 2 Part Mark Answ er Further Information 1 C D (A) B Total 1 Question number 3 Part Mark Answ er Furth er Information (a) 1 (b) 1 x = 3 Total 2 Question number 4 Part Mark Answ er Further Information 1 Total 1 Question number 5 Part Mark Answ er Further Information 1 Image translated right one square and down three squares. Total 1

3 © UCLES 2016 1112/02/O/N/16 [Turn over Question number 6 Part Mark Answ er Further Information 1 Total 1 Question number 7 Part Mark Answ er Further Information 1 Accept an answer which relates to lack of choice in response boxes or people might want to tick a 'no' box or both boxes. Total 1 Question number 8 Part Mark Answ er Further Information 1 Any whole number in the range 43 995 ≤ x < 44005 Total 1 Question number 9 Part Mark Answ er Further Information (a) 1 9 5 Accept equiv alent fraction, decimal or percentage . Do not accept in ratio form (e.g. 5 : 9). (b) 1 9 7 Accept equivalent fraction, decimal or percentage . Do not accept in ratio form (e.g. 7 : 9). Total 2

4 © UCLES 2016 1112/02/O/N/16 Question number 10 Part Mark Answ e r Further Information 1 40 000 000 or 40 million Total 1 Question number 11 Part Mark Answ er Further Information 1 Ticks Yes and gives a correct reason, e.g. • 50% for both but more women’s coats were sold. • 21 of 76 = 38, 21of 108 = 54 • 21 of 108 > 21of 76 or equivalent. Total 1 Question number 12 Part Mark Answ er Further Information 2 5 Award 1 mark for 22 or 27 seen. Total 2 Question number 13 Part Mark Answ er Further Information 2 34 (badges) Award 1 mark for sight of either of these: • 153 / 9 (= 17) • 92 (  153) Total 2

5 © UCLES 2016 1112/02/O/N/16 [Turn over Question number 14 Part Mark Answ er Further Information (a) 1 The following four additional combinations stated with no repetitions in table Red Yellow Red Green Green Yellow Green Green (b) 1 6 1 (or equivalent) Follow through from their (a) provided that at least 2 extra combinations were added in (a) and answer is > 0 , i.e. not 0/4 Total 2 Qu estion number 15 Part Mark Answ er Further Information (a) 1 t 4 (b) 2 8r + 2 r 2 For 2 marks accept: • 2r (4 + r) • 2r ( r + 4) Award 1 mark for • 2(4r + r 2) • 2(r 2 + 4 r) • r(8 + 2 r) • r(2 r + 8) • 8r seen • 2r 2 seen Total 3

6 © UCLES 2016 1112/02/O/N/16 Que stion number 16 Part Mark Answ er Further Information 2 Award 1 mark for: • 1 correct box ticked and no incorrect boxes ticked. • 2 correct boxes ticked and 1 incorrect box ticked.   Total 2 Question number 17 Part Mark Answ er Further Information 2 Accurately drawn net e.g. Award 1 mark if at most one face is missing or inaccurately drawn. Accept other correct accurate arrangements. Total 2 Question numbe r 18 Part Mark Answ er Further Information 1 128 (kilometres) Total 1

7 © UCLES 2016 1112/02/O/N/16 [Turn over Question number 19 Part Mark Answ er Further Information (a) 1 x 8 (b) 2 m t m 2 2 + Award 1 mark for a single fraction with denominator 2 m or numerator m + 2 t or m m 2 + mt 2 2 or m t m + 2 1 Total 3 Question number 20 Part Mark Answ er Further Information 2 Euros and supporting working e.g. 8.1 × 0.72 = 5.832 or 5.7 ÷ 0.72 = 7.916(6....) Allow figures 5.832 and 7.916(6…) to be rounded only as far as 1dp e.g. 7.92, not 7.91 Award 1 mark for 8.1 × 0.72 or 5.7 ÷ 0.72 (i.e. working shown but not evaluated) or Correct conversion (i.e. 5.832 or 7.916....) but with an incorrect dec ision of dollars . Total 2

8 © UCLES 2016 1112/02/O/N/16 Question number 21 Part Mark Answ er Further Information (a) 1 Any of these answers x = 2, y = 6 x = 3, y = 5 x = 4, y = 4 x = 5, y = 3 x = 6, y = 2 (b) 1 Any pair of values for m and n such that m – n = 4 and m , n are whole numbers greater than 1 e.g. m = 6, n = 2 m = 14, n =10 Total 2 Question number 22 Part Mark Answ er Further Information (a) 1 28(.336) (kg) (b) 2 38(.25…) (%) Award 1 mark for (25.3 – 18.3) ÷ 18.3 (implied by 7 ÷ 18.3) or 0.38 seen. or f or evidence of a correct alternative method such as (25.3 ÷ 18.3) – 1 ( – 1 can be seen or implied) or 1.38 seen. Total 3

9 © UCLES 2016 1112/02/O/N/16 [Turn over Question number 23 Part Mark Answ er Further Information 1 Rings July and gives a correct reason, e.g. • The modal interval was 70- 75 seconds in April but was 65- 70 seconds in July • The average time was faster in July • There were fewer longer times in July • There were more shorter times in July. • The July race finished in a shorter time. Total 1 Question number 24 Part Mark Answer Further Information 3 9 (minutes) Award 2 marks either for sight of both 2.25 (hours ) (or equivalent ) and 2.4 ( hours ) (o r equivalent) or for sight of 0.15 ( hours) (but not if 0.15 is given on answer line without unit change. ) Award 1 mark for si ght of either of 2.25 (hours ) (o r equivalent ) or 2.4 (hours ) (or equivalent ). or 40 90 and 50 120 Total 3

10 © UCLES 2016 1112/02/O/N/16 Question number 25 Part Mark Answ er Further Information (a) 1 5, 7, 9, 11 (b) 1 7, 12, 17, 22 Total 2 Question number 26 Part Mark Answ er Further Information 2 ($) 480 Award 1 mark for Either finding the mass in Kg of the seed the farmer needs, e.g. 0.01 × 120 000 (= 1200) or 1000 10 × 120 000 (= 1200) o r finding the cost of seed per square metre, i.e. 0.40 × 10/1000 (= $0.004) o r correct method with one error. Total 2 Question number 27 Part Mark Answ er Further Information 1 (C =) 45 G Total 1

11 © UCLES 2016 1112/02/O/N/16 [Turn over Question number 28 Part Mark Answ er Further Information 3 Rotation and 90° clockwise and centre (0, –1) Combinations of transformations score zero marks. Award 1 mark for each of: • Rotation • 90° clockwise • Centre (0, –1) Total 3

12 © UCLES 2016 1112/02/O/N/16 BLANK PAGE