Download [PDF] October 2018 CAIE P1 Mark Schemes 1111 English Cambridge Lower Secondary Checkpoint

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This document consists of 10 printed pages. IB18 10_1112_01/4RP © UCLES 2018 [Turn over Cambridge International Examinations Cambridge Secondary 1 Checkpoint MATHEMATICS 1112/01 Paper 1 October 2018 MARK SCHEME Maximum Mark: 50 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Markers were instructed to award marks. It does not indicate the details of the discussions that took place at an Markers’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the End of Series Report. Cambridge will not enter into discussions about these mark schemes. Mark scheme annotations and abbreviations M1 method mark A1 accuracy mark B1 independent mark FT follow through after error dep dependent oe or equivalent cao correct answer only isw ignore subsequent working soi seen or implied

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 2 of 10 Question Answer Marks Further Information 1 7.57 cao 2 sight of 7. (…) B1 Do not accept 7r4 or 7 74 on its own. 2 Less than 30 Equal to 30 More than 30     2 Award 2 marks for all correct. 2 correct B1 3 8 – 4 – 2 2 2 correct B1 4 8 : 7 2 Any correct not fully simplified ratio provided the units are the same e.g. 160 : 140, 16 : 14, 1.6 : 1.4, 1 : 0.875, 1 : ; < , < ; : 1, 1.14… : 1 etc. or correct numbers reversed, i.e. 7 : 8 B1 Anything with units e.g. 8 cm : 7 cm scores maximum 1 mark.

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 3 of 10 Question Answer Marks Further Information 5 Rings d and ticks ‘Angles on a straight line add up to 180°’. 1 Allow any unambiguous indication of the correct answer. 6(a) 1 Allow any unambiguous indication of the correct answer. 6(b) 1 Allow any unambiguous indication of the correct answer. 7(a) 13.8 1 7(b) 4500 1 8 ( y =) 63 2 28 ÷ 4 × 3 × 3 oe or 21 seen M1 e.g. 28 ÷ 4 × 3 ÷ 5 7, 4 252 oe 9 900 (cm) 3 Correct method e.g. 20 × 2 + 50 × 2 + 70 × 2 + 130 × 2 + 180 × 2 or 20 × 2 + 70 × 2 + 50 × 4 + 130 × 4 or answer 9 m M2 for correct method with only one numerical error or omission of one side 130 or 180 seen or 1 extra correct length marked on the diagram in any unit. M1 8.7 9.1 9.5 41.5 0 1 77 1

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 4 of 10 Question Answer Marks Further Information 10(a) GH or HG 1 Allow any unambiguous indication of the correct answer. 10(b) (x =) 70 2 Allow on second diagram next to x Missing angle in first quadrilateral is 70 ° or the letter x or 100 + 105 + 85 + x = 360 or better e.g. 360 – (100 + 105 + 85) or 360 – 290 or the missing angle value marked in the first quadrilateral is their x M1 May be seen on diagram. 11 1 (11) 12 (4) 2 two numbers that add up to 13 or An integer value less than 11 in the 0 −9 row and also an integer value of at least 12 in the 20 – 29 row B1 Condone 0 in the 0 −9 row

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 5 of 10 Question Answer Marks Further Information 12 54 and an explanation that includes one of the following pairs • 41 and 51 or equivalent fractions • 0.2 and 0.25 • 20% and 25% 1 Condone 54 and an explanation that includes one of the following pairs • 0.8 and 1.25 • 80% and 125% • 6 9 6 4 and 5 : 6 4 or equivalent fractions with common denominator Accept finding 8 9 and 9 8 of a number and comparing. Do not accept ‘fifth s are smaller than quarter s’ alone. May use diagrams as part of the explanation. 13     2 Allow any unambiguous indication of the correct answer. 2 correct B1

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 6 of 10 Question Answer Marks Further Information 14 208 (oe) e.g. 6 9, 8 5 4 , 0.4, 40% 3 either a sample space diagram showing all 20 correct outcomes (totals or pairs) e.g. + 2 3 4 6 + 2 3 4 6 1 3 4 5 7 1 1,2 1,3 1,4 1,6 1 3 4 5 7 1 1,2 1,3 1,4 1,6 2 4 5 6 8 2 2,2 2,3 2,4 2,6 3 5 6 7 9 3 3,2 3,3 3,4 3,6 4 6 7 8 10 4 4,2 4,3 4,4 4,6 or for a list of all 20 correct outcomes (totals or pairs) and none incorrect/extra. M2 finding at least 16 correct outcomes (totals or pairs) or identifying all 8 correct outcomes (totals or pairs) where the sum is 7 or more M1

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 7 of 10 Question Answer Marks Further Information 15 2 any box correct or follow through for their 45 being their 450 000 ÷ 10 000 B1 16 × 8 0.2 0.8 6.4 0.16 0.3 2.4 0.06 3 Award 3 marks for all 4 correct. either 0.8 correct with two of 0.16, 2.4 and 0.06 correct or 0.8 wrong but all remaining entries correct allowing for follow through for 0.2 × their 0.8 B2 either 0.8 correct or 2.4 and 0.06 correct or 0.8 wrong but 2 other entries correct allowing for the follow through of 0.2 × their 0.8 B1 Only award if 3 or B2 are not already scored. 4500 450 000 45 450

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 8 of 10 Question Answer Marks Further Information 17(a) Primar y Secondar y    1 All three must be correct. 17(b) A correct explanation e.g. There is no box for 0 / zero / none/ never / do not use or There is no box for 6 / it should say more than 5 times or it is not an exhaustive list 1 Do not allow e.g. • they may not remember how many times • there are limited options • 2 or 3 should not be grouped

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 9 of 10 Question Answer Marks Further Information 18 Median for normal toothbrush = 23 and Median for electric toothbrush = 16 and A suitable conclusion, following through from their averages, e.g. ‘Patients who use an electric toothbrush have healthier teeth (than those who don’t).’ 3 Condone electric is better. Correct value for normal toothbrush Median = 23 Accept mean 22.3 B1 B1 can only be scored if the number matches the word. Allow mean = 22 Correct value for electric toothbrush Median = 16 Accept mean 17.7 B1 B1 can only be scored if the number matches the word. Allow mean = 18 A suitable conclusion following through from their averages. or A correct conclusion with no averages found i.e. that people who use an electric toothbrush have healthier teeth. B1 Note use lowest value for conclusion. Condone electric is better. Conclusion must be consistent with their numbers, if present, if blank conclusion must be correct. 19 408 (cm 2) 3 6 × 15 + 8 × 15 + 10 × 15 + 21× 6 × 8 × 2 oe M2 Implied by e.g. 90 + 120 + 150 + 24 + 24 or better Condone one out of the five areas being incorrect or missing for M2. Two correct from 90, 120, 150, 24 and 24 or 360 or 48 B1

1112/01 Checkpoint Mathematics - Mark Scheme October 2018 Page 10 of 10 Question Answer Marks Further Information 20 112.5 (litres) 2 correct method, e.g. 7.5 × 60 × 0.25 oe or 1 litre in 4 sec and 7.5 min = 450 sec and 450 ÷ 4 M1 21(a) 2 1 Allow ‘order 2’. 21(b) 0 or none or zero 1 22 Rotation 90° anticlockwise about (0, 0) 3 Combination of transformations can score maximum M1. Rotation B1 Do not allow e.g. turn 90° anticlockwise oe B1 Allow equivalents, e.g. quarter turn anticlockwise or + 90° or 270° clockwise. Do not accept 90° without the + sign. Centre (0, 0) (or the origin or O) B1 Final image of triangle shown at co-ordinates (–5, 1) (–5, 3) (–2, 1) M1 Award only if 0 scored. Condone vertices only for M mark. 23 –0.5 or – 21 1 Accept any equivalent fraction e.g. – 4 2 Do not accept e.g. –0.5 x