Download [PDF] October 2021 CAIE P1 Mark Scheme 1112 Mathematics Cambridge Lower Secondary Checkpoint

File Information

Filename:	[PDF] October 2021 CAIE P1 Mark Scheme 1112 Mathematics Cambridge Lower Secondary Checkpoint.pdf
Filesize:	434.67 KB
Uploaded:	15/03/2022 17:16:29
Keywords:	october 2021 caie p1 mark scheme 1112 mathematics cambridge lower secondary checkpoint pdf
Description:	Download file or read online CAIE Cambridge lower secondary checkpoint past exam paper Mathematics 1112/01/O/N/20 October/November 2021 mark schemes paper 1 - Cambridge Assessment International Education.
Downloads:	830

File Preview

Download Urls

Short Page Link

https://www.edufilestorage.com/936

Full Page Link

https://www.edufilestorage.com/936/PDF_October_2021_CAIE_P1_Mark_Scheme_1112_Mathematics_Cambridge_Lower_Secondary_Checkpoint.pdf

HTML Code

<a href="https://www.edufilestorage.com/936/PDF_October_2021_CAIE_P1_Mark_Scheme_1112_Mathematics_Cambridge_Lower_Secondary_Checkpoint.pdf" target="_blank" title="Download from eduFileStorage.com"><img src="https://www.edufilestorage.com/cache/plugins/filepreviewer/4788/pdf/150x190_middle_46f4e7862b1eb5bd4935adbbba5d79e8.jpg"/></a>

Forum Code

[url=https://www.edufilestorage.com/936/PDF_October_2021_CAIE_P1_Mark_Scheme_1112_Mathematics_Cambridge_Lower_Secondary_Checkpoint.pdf][img]https://www.edufilestorage.com/cache/plugins/filepreviewer/4788/pdf/150x190_middle_46f4e7862b1eb5bd4935adbbba5d79e8.jpg[/img][/url]

[PDF] October 2021 CAIE P1 Mark Scheme 1112 Mathematics Cambridge Lower Secondary Checkpoint.pdf | Plain Text

This document has 10 pages. Any blank pages are indicated. IB21 05_1112_01/4RP © UCLES 2021 [Turn over Cambridge Lower Secondary Checkpoint MATHEMATICS 1112/01 Paper 1 October 2021 MARK SCHEME Maximum Mark: 50 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Markers were instructed to award marks. It does not indicate the details of the discussions that took place at a Markers’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the End of Series Report. Cambridge will not enter into discussions about these mark schemes.

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 2 of 10 Mark scheme annotations and abbreviations M1 method mark A1 accuracy mark B1 independent mark FT follow through after error dep dependent oe or equivalent cao correct answer only isw ignore subsequent working soi seen or implied

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 3 of 10 Question Answer Mark Further Information 1 5 : 7 5 cao 1 2 circumference, radius and diameter 2 In correct order. Accept reasonable misspellings. one correct B1 3 3 12 6 14 5 4 4 2 13 2 for either 6 or 2 in the correct place. B1 4 [x =] 5 2 –3x = 2 – 17 or 3x = 17 – 2 or better M1 Accept correct division of all terms by 3 or –3 e.g. 5 ; 7 – x = 6 7 for M1 5 (a) 1 Accept diagram drawn in any position but must be correct orientation (b) 4 1 (c) 27 1

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 4 of 10 Question Answer Mark Further Information 6 True False []   1 Accept any clear indication 7 9 ; 6 4 4 cao 2 6 < 9 5 4 4 4 oe fraction B1 Note an equivalent fraction does not include decimals B0 for e.g. 6

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 5 of 10 Question Answer Mark Further Information 11 1 Two correct triangles ringed and no others. Ignore ring around A Accept any clear indication. 12 7.22 cao 2 Do not accept recurring notation e.g. 7. 26 26 , 7. 22 $ $ $ $, 7.22… award B1 for these 7.2 or 7.22[2…] or for their more accurate value correctly rounded to 2dp B1 Could be in working. 13 0.1 or 5 5 4 or 10 –1 1 14 (a) 3.198 2 For the figures 3198 with a decimal place at any point (including before or after any zeros) or a correct method, including correct placement of decimal point, with one arithmetic error M1 e.g. M1 for Error in the first 6 but everything else correct (FT the initial error). e.g. M0 for missing the 0 is not an arithmetic error, or e.g. adding tenths to units (even if the 0 is there) due to misalignment of columns or misplacement of decimal point in 738 and 2460 implied by figures 984 in answer Error is likely to be one incorrect digit in this correct working 246 x 13 738 2460 3198 246 x 13 638 2460 3098 and answer 3.098 246 x 13 738 246 984

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 6 of 10 Question Answer Mark Further Information (b) 3.2 1 Do not accept with trailing zeros e.g. 3.200 FT from their answer to part (a) provided a more accurate figure shown. 15 (a) or or 1 In any orientation e.g. (b) 1 In any orientation. Do not accept a square. 16   1 In correct order. Accept any clear indication.

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 7 of 10 Question Answer Mark Further Information 17 6 and 7 1 In correct order. Do not accept √36 and √49 or 6 2 and 7 2 18 5 7 : 4 3 Accept equivalent fractions. Note it is not an equivalent fraction if it contains decimals, which is common in this question e.g. award M2 for :. 9 7 4 1  @ 5 6 7 4  9 7 4A or better or for l1  @ 5 6 7 4  9 7 4A p J2 correctly evaluated with one incorrect numerator from 12 or 5 M2 M2 implied by 5 7 7 4 or equivalent fraction For M2 accept other correct equivalent fractions using a common denominator. i.e. no more than one arithmetic error 5 6 7 4 and 9 7 4 or : H 6 > 9 H 5 : H 9 or better or for 1  @ 5 6 7 4  9 7 4A with one incorrect numerator or for evaluating correctly @ 1 F ? ?A J2 M1 Accept other correct equivalent fractions using a common denominator. M1 implied by 5 ; 7 4 oe Where ? ? comes from any attempt to process 6 9 and 5 : Award M1 for @ 1 F ? ?A J2 even if they work in decimals provided their answer is correctly converted back to a fraction. 19 –1, 1, 9 1 In correct order. 20 (a) 1 [km/h] not from wrong working 1 Accept –1 [km/h]

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 8 of 10 Question Answer Mark Further Information (b) A comparison that identifies Monday as fewer cars and faster than Thursday. e.g. Monday with less cars/Thursday as more cars and Monday, as faster speeds/Thursday, as slower speeds /average for Monday is greater than average for Thursday 1 If no comparison accept correct supporting figures to imply comparison e.g.  12 cars Monday and 22 cars Thursday  Median is 59.5 on Monday and 44 on Thursday Accept mean, median or mode for “average” Ignore incorrect figures only if there is a correct comparison e.g. “Monday has less cars and the median for Monday is 59.5 which is greater than the median for Thursday which is 47” Comments with no reference to Thursday/Monday are unlikely to score, they’re usually general comments about traffic conditions on the road rather than comments about the data and are often just a rewording of the question. However, you might be able to imply the days they mean by figures/calculations next to the stem and leaf diagram. 21 (a) 5 5 9 4 1 Accept any equivalent answer e.g. 0.22, 22% Do not accept a ratio 11:50 or in words e.g. 11 out of 50   (b) 3 1   (c) 2 1   22 28 2 8 J 6 ; or better M1 Accept equivalent methods, e.g.

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 9 of 10 Question Answer Mark Further Information < 5 J 6 ;, 9 : ; J 6 ;, 8 H ; 6, 8 × 3.5, 56 ÷ 2 counting on 2 bags is 7 4 bags is 14 8 bags is 28 23 180 1   24 15 [cm] not from wrong working 1 Just look out for working 60 – 45 no need to check otherwise   25 5.264 and 9400 2   One correct B1   26 30 [minutes] 2   Any of  2 [hours]  2.5 [hours] oe  120 [minutes]  150 [minutes]  0.5 [hours]  Half an hour B1 27 16 × 10 −2 175 000 ÷ 10 4 0.48 × 10 4 7 ÷ 10 −3 2 Accept values given as 0.16 17.5 4800 7000 or a combination. Accept 5 : 5 4 4 for 0.16

1112/01 Lower Secondary Checkpoint – Mark Scheme October 2021 PUBLISHED © UCLES 2021 Page 10 of 10 Question Answer Mark Further Information For one incorrectly placed but the rest in the correct order. or for sight of at least three of 4800, 0.16, 7000 or 17.5 B1 Accept 5 : 5 4 4 for 0.16 28 90° [anticlockwise] and translation and 6 right, 7 up or @6 7A 3 Accept equivalents, e.g. 270° clockwise, −270° Award 0 if extra properties or transformations mentioned Award 0 if extra transformations mentioned treat extra properties as choice Any two of the three elements correct. B2 For one of the three elements correct. or for correctly showing on the grid the image of A under a rotation, centre O, by 90°, anticlockwise. B1 Ignore other shapes.