Download [PDF] April 2019 CAIE P2 Mark Schemes 1112 Mathematics Cambridge Lower Secondary Checkpoint

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This document consists of 8 printed pages. © UCLES 2019 [Turn over Cambridge Assessment International Education Cambridge Secondary 1 Checkpoint M AT HEM AT ICS 1112/02 Paper 2 April 2019 MARK SCHEME Maximum Mark : 50 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Markers were instructed to award marks. It does not indicate the details of the discussions that took place at an Markers’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the End of Series Report. Cambridge will not enter into discussions about these mark schemes. M ark scheme annotations and abbreviations M1 method mark A1 accuracy mark B1 independent mark FT follow through after error dep dependent oe or equivalent cao correct answer only isw ignore subsequent working soi seen or implied

1112/02 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 2 of 8 Question Answ er Mark Further Information 1(a) 77 (°F) 1 1(b) 1 Allow any equivalent e.g. × 9 5 for ÷ 1.8 2 45 1 3 1 Allow any unambiguous indication. 4(a) 249 000 cao 1 4(b) 52.7 cao (square kilometres) 1 5 2 The orientation of the image is correct but it is in the incorrect position or 3 or 4 of the 5 vertices are in the correct position. B1 6(a) x = 4 y = 4 x y = 4 x + y = 4 1 Accept any unambiguous indication . 6(b) 1 Line must extend at least as far as (0, 2) and (6, 2).

1112/02 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 3 of 8 Question Answ er Mark Further Information 7(a) An answer between 6.4 (metres) and 7.2 (metres) inclusive 1 7(b) Rectangle measuring 1.5 cm by 2 cm (± 2 mm) 1 This can be positioned anywhere 8(a) 2.25 (km) 2 sight of 2250 or 0.025 or 90 × 25 ÷ 1000 or a correct conversion of their m to km B1 = e.g. 90 =? 25 = 3.6 with answer 0.0036 = 8(b) 72 2 90 14+ =or 90 5 =or 18 (number of lengths in one share) or for 1800 ( m ) or for 1.8 (km) (total distance Carlos swims on his front ) B1 9(a) 1 Both equations must be indicated for the mark. Allow any unambiguous indication. 9(b) x = −2= y = −3= 1 x and y must both be correct for the mark. 10(a) (S = ) 2 π ab oe final answer 1 Note in parts (a) and (b) allow 3.14, 22/7 for π=== Possible expressions for S are ab π 2 1 and 2 π ÷ ab , allow e.g. 1.57 ab The order of the multiplicands can vary. 10(b) 252 to 253 (cm 3) 2 Accept answer in terms of pi , e.g. 80.4 π, 10051 ������������ 125 π=? 7.6 ? 9.2 2=÷=8 oe = M1 = =

1112/02 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 4 of 8 11(a) 56.06… or 56.1 and Too big 1 11(b) (x =) 5.7 cao 1 12 (a) b > m b ≥ m b < m b ≤ m 1 Accept any unambiguous indication. 12 (b) a < 21b 1 Or equivalent, e.g. 2 a < b, b > 2 a , 2 1b > a 13 52.9?(%) or 53 (%) 2 Allow 52 17 16 % but not 900 17 % 45 seen B1 or ������������ 85 correctly converted to a percentage. M1 Only if B1 not awarded. To a minimum of 2sf 10 + 15 + 20 ×100 85

1112/02 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 5 of 8 14 2 A triangle of correct size and orientation but in the wrong position or for 2 correct vertices plotted or a correct enlargement using centre C but with SF 2 or 4 . B1 15 (a) Point plotted at (1.8, 9.5) 1 15 (b) Answer between 8 (seconds ) and 10 (seconds ) inclusiv e. 1 16 77 (cm) 780 (mm) 7.6 (m) 0.075 (km) 2 Accept lengths written in different units . Three values in the correct order or reverse order . B1

1112/02 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 6 of 8 17 Ticks “Chen earned a bonus” and gives correct supporting value, e.g. • sight of 2.859… (km / l) • sight of 98 .0357… (litres) •= sight of 274.5 (km) and 268.8 (km) 2 Allow rounded or truncated values to at least 2 sf but do not allow=2.8= alone without the calculation. = If no box ticked allow 2 marks =if =decision is clear in= the working and there is a correct supporting value. sight of any of • 61 × 4.5 or 274.5 • 96 × 2.8 or 268.8 • 61 × 4.5 ÷ 96 or 2.859… •= 4.5 ? 61= ÷=2.8 =or==98.0 357 ? = B1 = Allow rounded or truncated values to at least 2 sf but= do not=allow 2.8 alone without the calculation. = = 18 = = = = = True = False =    1 19 = One of= = a = 1 or a = 2 or a = 3 or a = 4 b = 9 b = 8 b = 7 b = 6 2 A correct relationship connecting a and b, e.g. • a + b = 10 • 1 2( a + b) × 6 = 30 • 3( a + b) = 30 • = 6( – ) 6 – 30 2 ba b = • += 6( – ) 6 30 2 ba a = = M1 = Relationship= can =be implied by two positive answers= that add to 10. = = Do not allow 10 and 0 for a and b. a and b can be numerical for the M1 mark e.g. ½ (7 + 3) × 6 = 30

1112/02 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 7 of 8 20 (Film) B and correct working. The working should enable a comparison of the films to be made, e.g. sight of • (1 :) 1.727… and (1 :) 1.4 • 0.578… (: 1) and 0.714… (: 1) • 0.366… and 0.416… • 0.633… and 0.583… • 22/60 and 25/60 • 55:95 and 55:77 •=77:133= and 95:133 2 Accept equivalent fractions and percentages . Other values are possible. Allow figures rounded or truncated to an appropriate number of significant figures in order to compare. Sight of any one acceptable value . M1 Accept equivalent fractions and percentages . 21 25 (%) 3 A correct method, e.g. • 40 ( 100) 160 × • ( ) 100 102.4) (8 1.6 8 25.6) ( 8 0.4 2 × = × × = × or for 12.8 or 102.4 and 0.4 × 82 or 25.6 M2 Sight of any of: • 160% (= 1.6) •=12.8 or 102.4 or 0.4 ? 82 or 25.6 B1 Only if M2 not awarded. 22 4200  cm 3 54 000  mm 3 45 litres 52  000 ml 1 Accept any unambiguous indication .

1112/02 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 8 of 8 23 Ticks n o and correct reason with supporting values involving all three age groups , e.g. • percentages that can remember are 80%, 70% and 65% (and these decrease with age) • percentages that cannot remember are 20%, 30% and 35% (and these increase with age) • 26 out of 40 is the same as 13 out of 20 and this is lower than 16 and 14 2 Accept an answer that combines two age groups e.g. compares people under 30 and people over 30 using 30 and 26 (can remember) or 10 and 14 (can’t remember). Two correct comparative fractions, decimals or percentages or T hree comparable figures e.g. • 20, 13 and 7 (halving bottom row) • 16, 14 and 13 or 4, 6 and 7 (halving bottom row) • 32, 28 and 26 or 8, 12 and 14 (doubling top two rows) or A correct comparative statement between age groups B1 Other multiples may be possible Also may be shown in the table. 24 6400 3 3 120 and 3 30 and 3 50 truncated or 40 and 10 and 16 M2 May be seen on diagram. Do not allow 180 000 27 for 2 marks Conversion of 1.2 m into 120 (cm ) or Correct truncation of B1 Implied by 40 or 180 000 or 6666 to 6667 Implied by 16 25 3.5 and ?3.5 1 Either order. Allow 7 2 and – 7 2. 50 3