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Download [PDF] April 2019 CAIE P1 Mark Schemes 1112 Mathematics Cambridge Lower Secondary Checkpoint
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This document consists of 7 printed pages and 1 blank page. © UCLES 2019 [Turn over Cambridge Assessment International E ducation Cambridge Secondary 1 Checkpoint M AT HEM AT ICS 1112/01 Paper 1 April 2019 MARK SCHEME Maximum Mark : 50 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Markers were instructed to award marks. It does not indicate the details of the discussions that took place at an Markers’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the End of Series Report. Cambridge will not enter into discussions about these mark schemes. Mark scheme annotations and abbreviations M1 method mark A1 accuracy mark B1 independent mark FT follow through after error dep dependent oe or equivalent cao correct answer only isw ignore subsequent working soi seen or implied
1112/01 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 2 of 8 Question Answ er Mark Further Information 1 ( y =) 5 1 2 7 1 3 1.5 ( l) 1 Allow 1.5(00) allow 1 1 2 Do not accept 1500 m l 4 375 (g) 1 5 103 oe 1 Allow equivalents e.g. 0.3, 6 20, 12 40 as final answer 6 1 Accept any unambiguous indication. Both correct . 7 1 Accept any unambiguous indication. 8 3.81 1 9 12 (days) 1 10 840 (cm 3) 2 7 ? 4 ? 3 ? 10 oe or sight of 280 or 84 or 120 or 210 M1 11 Ticks Rice B and gives 150 and 125 2 Do not award any marks for choice of rice B without a correct explanation. Accept correct explanation if no box is ticked. • With rice B, you get 150 g extra, but with rice A you only get 125 g extra. 150 or 125 seen or 625 and 900 seen B1
1112/01 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 3 of 8 Question Answ er Mark Further Information 12 Ticks Lily and gives correct supporting work e.g. • 11 2 = 121 or 121 is 11 • 121 is closer (to 120 than 100) 1 Do not award any marks for choice of Lily without a correct explanation. Accept correct explanation if no box is ticked , provided the decision of Lily being closer is clear . 13 61 (and) 67 1 Must have just these two . 14 Coin C ticked 1 Allow any unambiguous indication. 15 ? ? ? ? 2 3 correct signs B1 16 36(?) 1 17 (a) 2 (hours) 18 (minutes) 1 17 (b) 12 :36 (pm) 2 sight of 15:10, 15:30, 15:58 or 15:06 or 12:36 not as final answer B1 e.g. circled on table 18 (a) 117 cao 1 18(b) 49 5 cao 1 Do not accept 2 5 7
1112/01 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 4 of 8 19(a) A fully correct frequency diagram : 2 The frequency diagram must be fully correct for 2 marks, i.e . bars must touch and have the correct widths and heights. Accept frequency polygon with values plotted at the midpoints, ignore vertical lines and allow joining or not joining to axes . The diagram contains only one error. M1 Examples of one error are: • having gaps between bars provided bars touch midpoints , • drawing 5 lines rather than 5 bars provided lines are at midpoints , • drawing just midpoints and not joining up (and no other lines) , • one incorrect bar height or one incorrect point on the frequency polygon, • consistently using start (or end) of class intervals for a frequency polygon 19(b) Ticks ?Rajiv is not correct? and gives a correct reason, e.g. • It is in 17 ≤ L < 18 • More than half the values are less than 18 (cm). • Less than half the values are 18 (cm) or more. 1 Accept reference to either the 20 th or 21 st or 20.5 th value being the median. Do not accept e.g. 21 values are less than 18, unless there is some indication that it should be half the values. Do not accept any reference to the interval with the ‘median frequency ’. Do not award any marks for choice of correct without a correct explanation. Accept correct explanation if no box is ticked e.g. Rajiv is not correct because it is in 17 ≤ L < 18 20 282 1
1112/01 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 5 of 8 Question Answ er Mark Further Information 21 Primary Secondary 1 Allow any unambiguous indication. 22 ($) 15 1 23 (a) 35 1 23 (b) 13 or answer to (a) ? 7 ? ? 5 and answer to (b) is 6 ? ? 7 1 Provided not spoilt by evaluating incorrectly . 24(a) 5(x – 1) = 2( x + 8) or 5x – 5 = 2 x + 16 1 isw after seeing correct answer. 24(b) 30 (cm) 2 If answer in part (a) is incorrect Award 2 FT for correctly solving their (a) (as long as their (a) is linear) and correctly substituting their x to find the length of one of the lines. x = 7 or correctly finding the length of the line using their 7 or correctly solving their (a) (as long as their (a) is linear) B1 Condone an answer of 7 for B1 . 25 (3, 10) 2 One correct coordinate B1
1112/01 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 6 of 8 Question Answ er Mark Further Information 26 17 36 3 Provided 6 and 8 are not incorrect . A complete correct sample space diagram + 1 2 4 6 6 8 1 2 3 5 7 7 9 2 3 4 6 8 8 10 4 5 6 8 10 10 12 6 7 8 10 12 12 14 6 7 8 10 12 12 14 8 9 10 12 14 14 16 or a complete sample space diagram, with 6 and 8 correct but other errors and with correct follow through for probability B2 Identifying 6 and 8 (the two missing numbers from the spinner) or a complete correct sample space diagram using their values (ignoring grey boxes) or ℎ ℎ 9 36 from a complete diagram B1 Note : may be on spinner or in top row or in first column of table. 27 Positive gradient Zero gradient Negative gradient y = 4 x + 1 y = 3x – 5 y = –1 y = – 6x x + y = 11 2 Allow correct equivalent rearranged equations . 2 correctly placed equations B1 28(a) p = 56( °) q = 20 (°) 2 One correct value B1
1112/01 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 7 of 8 Question Answ er Mark Further Information 28(b) Ticks Not correct and gives a correct reason, e .g. • in a kite, two angles are equal • a kite has one pair of equal angles • (BCDE) doesn’t have any equal angles • a kite has a line of symmetry • a kite is symmetrical • (BCDE) doesn’t have any lines of symmetry • (BCDE) doesn?t have two pairs of equal sides . 1 Do not accept a reason based measured sides or a reason based on one pair of sides. Others answers are acceptable e.g. • 132 doesn’t equal 118 • Angles E and C are not the same But do not allow • E and C are not the same 29(a) 2 Allow any orientation of a 4 cm by 2 cm rectangle. Do not allow internal lines. A rectangle with one dimension correct with no internal lines or a 2 cm by 4 cm rectangle ignoring internal lines . B1 29(b) or with some or all hidden lines shown 1 30 11 12 2 7 6 oe (finding the difference) or 11 6 oe (finding the sum) or a value equivalent to 11 12 B1 e.g. 5.5 6
1112/01 Cambridge Secondary 1 Checkpoint – Mark Scheme April 2019 PUBLISHED Page 8 of 8 BLANK PAGE